modulus within a modulus equation
Break it up into two cases.
1. less than or equal to 0
2. greater than 0
In each of those cases, you can remove the modulus bars, and thus, you can solve it. i.e. if less than 0, than |2x| becomes -2x.
Hope this helps.
[ Ð 5x - Ðx^2Ð Ð ]
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Break it up into two cases.
1. less than or equal to 0
2. greater than 0
In each of those cases, you can remove the modulus bars, and thus, you can solve it. i.e. if less than 0, than |2x| becomes -2x.
Hope this helps.
[ Ð 5x - Ðx^2Ð Ð ]