The limit would be equal to 0. As x increases, the -1 and +2 will have less impact, as will the coefficients, so you are left with (√x)/x. As x increases, this approaches 0. Therefore, the limit is equal to 0.
lt x?? : f(x)/g(x) = lt: f'(x)/g'(x) via L'Hopital rule... f '(x) = sixteen/(?16x-a million) g '(x)= 2 f '(x)/g '(x) = 8/(?16x-a million) lt x?? f '/ g' = 0 the cut back exists considering the two numerator and denominator a non-end and differentiable x>a million/sixteen.
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The limit would be equal to 0. As x increases, the -1 and +2 will have less impact, as will the coefficients, so you are left with (√x)/x. As x increases, this approaches 0. Therefore, the limit is equal to 0.
lt x?? : f(x)/g(x) = lt: f'(x)/g'(x) via L'Hopital rule... f '(x) = sixteen/(?16x-a million) g '(x)= 2 f '(x)/g '(x) = 8/(?16x-a million) lt x?? f '/ g' = 0 the cut back exists considering the two numerator and denominator a non-end and differentiable x>a million/sixteen.