Can you go through it step by step?
Thanks:)
(3 - √4) = 3 - 2 = 1
(2 - √4) = 2 - 2 = 0
DIVISION BY ZERO IS UNDEFINED !
You have given a BAD problem !
euclid
Going through it step by step, you can see there is no solution. The square root of 4 is 2, so you have
(3-2)/(2-2) or 1/0, which is an undefined value.
(3 - â4)/(2 - â4)
= (3 - â4)(2 + â4)/(2 - â4)(2 + â4)
= 6 - 4 + â4(3 - 2)/0
= (2 + â4)/0
= undefined
The reason that the result of a division by zero is undefined is the fact
that any attempt at a definition leads to a contradiction.
{ (3 - â4) / (2 - â4) } * {(2 + â4) / (2 + â4)} --> (multiply by the conjugate of the denominator.).
= { 6 + â4 - 4} / 0
= { 2 + 2} / 0
= undefined answer
In the case of limits...
Multiply both sides by the conjugate of the denominator = (2 + â4)
=> (3 - â4)(2 + â4) / (2 - â4)(2 + â4)
Opening brackets, we have;
(6 + 3â4 - 2â4 - 4) / (4 - 2â4 + 2â4 - 4)
(6 - 4 + â4) / (0)
(2 + â4) / 0
Where â4 = 2
= (2 + 2)/0 = 4/0 = 0
(3 - â4)/(2 - â4) --- â4 is 2, then
= (3 - 2)/(2 - 2)
= 1/0
= â --- Undefined ...Ans.
This question is not valid as square root of four is two, and hence the denominator would become zero.
3- sq rt 4 * 2 +sq rt 4
-----------------------------------------------------------------------------------------------
2-sq rt 4 * 2 + sq rt 4 0 undefined because you cant divide by 0
3 - sq rt 4 2+sqrt 4
==============
2 -sq rt 4 0/0 0/0
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Answers & Comments
Verified answer
(3 - √4) = 3 - 2 = 1
(2 - √4) = 2 - 2 = 0
DIVISION BY ZERO IS UNDEFINED !
You have given a BAD problem !
euclid
Going through it step by step, you can see there is no solution. The square root of 4 is 2, so you have
(3-2)/(2-2) or 1/0, which is an undefined value.
(3 - â4)/(2 - â4)
= (3 - â4)(2 + â4)/(2 - â4)(2 + â4)
= 6 - 4 + â4(3 - 2)/0
= (2 + â4)/0
= undefined
The reason that the result of a division by zero is undefined is the fact
that any attempt at a definition leads to a contradiction.
{ (3 - â4) / (2 - â4) } * {(2 + â4) / (2 + â4)} --> (multiply by the conjugate of the denominator.).
= { 6 + â4 - 4} / 0
= { 2 + 2} / 0
= undefined answer
In the case of limits...
(3 - â4)/(2 - â4)
Multiply both sides by the conjugate of the denominator = (2 + â4)
=> (3 - â4)(2 + â4) / (2 - â4)(2 + â4)
Opening brackets, we have;
(6 + 3â4 - 2â4 - 4) / (4 - 2â4 + 2â4 - 4)
(6 - 4 + â4) / (0)
(2 + â4) / 0
Where â4 = 2
= (2 + 2)/0 = 4/0 = 0
(3 - â4)/(2 - â4) --- â4 is 2, then
= (3 - 2)/(2 - 2)
= 1/0
= â --- Undefined ...Ans.
This question is not valid as square root of four is two, and hence the denominator would become zero.
3- sq rt 4 * 2 +sq rt 4
-----------------------------------------------------------------------------------------------
2-sq rt 4 * 2 + sq rt 4 0 undefined because you cant divide by 0
3 - sq rt 4 2+sqrt 4
==============
2 -sq rt 4 0/0 0/0