Verified answer

-2(x - 3) ≥ 5 - (x + 3)

-2x + 6 ≥ 5 - x - 3

6 - 2 ≥ - x + 2x

4 ≥ x

For the moment, forget the inequality and just do the simple algebra ..........

–2(x – 3) ≥ 5 – (x + 3) --->

-2x + 6 ≥ 5 - x - 3 ---->

-2x + x ≥ 5 - 3 - 6 --->

- x ≥ -4 ..... Here's where you need to know something about inequalities.

If I divide by a negative number, I have to swith the inequality around:

-x/-1 ≥ -4/-1 ..... here's the switch ----->

x ≤ 4 .... The answer

Since u mentioned u dont know the RHS part let me help u on that,

5-(x+3)

5-x-3

5-3-x

2-x

-2x+6 ≥ 2-x

so you have –2(x – 3) ≥ 5 – (x + 3)

you can distribute: -2x+3>= 5-x-3

if you add x to both sides you'll get -x+3>= 5-3

if you simplify a little bit you will get -x+3>= 2

now if you substract 3 to both sides it will get -x>=-1

and finally if you multiply the relation with -1 you'll get x<=1

(if you multiply an inequality with a negative number it will change the sense of the inequality)