Put s = sinx, c = cosx. Then (4-4s)(4+4s) =
16(1-s)(1+s) = 16(1-s^2) = 16c^2.
Remember that (a+b)(a-b) = a²-b² ..............[1]
..........(4 − 4 sin x)(4 + 4 sin x)
has the same format as (a+b)(a-b) if we let a = 4 and b = 4 sin x.
Using [1], we have
..........(4 − 4 sin x)(4 + 4 sin x) = 4² - (4 sin x)²
....................= 16-16 sin²x............ANS
........................// You can also simplify the answer
....................= 16(1- sin²x)............ANS
....................= 16 cos²x.................ANS
==> 16 - 16sin^2(x)
==> 16(1 - sin^2(x))
==> 16 cos^2(x)
(4 - 4sin(x)) (4 + 4sin(x)) = 4² - (4sin(x))²
= 16 - 16sin²(x)
= 16(1 - sin²(x)
= 16cos²(x)
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Answers & Comments
Put s = sinx, c = cosx. Then (4-4s)(4+4s) =
16(1-s)(1+s) = 16(1-s^2) = 16c^2.
Remember that (a+b)(a-b) = a²-b² ..............[1]
..........(4 − 4 sin x)(4 + 4 sin x)
has the same format as (a+b)(a-b) if we let a = 4 and b = 4 sin x.
Using [1], we have
..........(4 − 4 sin x)(4 + 4 sin x) = 4² - (4 sin x)²
....................= 16-16 sin²x............ANS
........................// You can also simplify the answer
....................= 16(1- sin²x)............ANS
....................= 16 cos²x.................ANS
==> 16 - 16sin^2(x)
==> 16(1 - sin^2(x))
==> 16 cos^2(x)
(4 - 4sin(x)) (4 + 4sin(x)) = 4² - (4sin(x))²
= 16 - 16sin²(x)
= 16(1 - sin²(x)
= 16cos²(x)