https://www.youtube.com/watch?v=Y5zCUpQy6Rw
Hola
(7/(x + 1)) + (15/(3 x - 1)) = 8
(7(3 x - 1)/(x + 1)(3 x - 1)) + (15(x+1)/(x + 1)(3 x - 1)) = 8
(21 x - 7 + 15 x + 15) /(x + 1)(3 x - 1) = 8
36 x + 8 = 8 (x + 1) (3 x - 1)
8 (3 x^2 + 2 x - 1) = 36 x + 8
24 x^2 + 16 x - 8 = 36 x + 8
24 x^2 + 20 x - 16 = 0
6 x^2 + 5 x - 4 = 0
FÓRMULA ECUACIÓN CUADRÁTICA
x₁;x₂ = { -(b) ± √[(b)² - 4(a)(c)] }/(2(a))
x₁;x₂ = { -(5) ± √[(5)² - 4(6)(-4)] }/(2(6))
x₁;x₂ = { -5 ± √[ 25 + 96] }/(12)
x₁;x₂ = { -5 ± √[121] }/(12)
x₁;x₂ = { -5 ± 11 }/(12)
Primera solución
x1 = (-5 - 11)/12 = -16/12
x1 = -4/3
************
Segunda solución
x2 = (-5 + 11)/12 = 6/12
x2 = 1/2
Verificado
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Answers & Comments
https://www.youtube.com/watch?v=Y5zCUpQy6Rw
Hola
(7/(x + 1)) + (15/(3 x - 1)) = 8
(7(3 x - 1)/(x + 1)(3 x - 1)) + (15(x+1)/(x + 1)(3 x - 1)) = 8
(21 x - 7 + 15 x + 15) /(x + 1)(3 x - 1) = 8
36 x + 8 = 8 (x + 1) (3 x - 1)
8 (3 x^2 + 2 x - 1) = 36 x + 8
24 x^2 + 16 x - 8 = 36 x + 8
24 x^2 + 20 x - 16 = 0
6 x^2 + 5 x - 4 = 0
FÓRMULA ECUACIÓN CUADRÁTICA
x₁;x₂ = { -(b) ± √[(b)² - 4(a)(c)] }/(2(a))
x₁;x₂ = { -(5) ± √[(5)² - 4(6)(-4)] }/(2(6))
x₁;x₂ = { -5 ± √[ 25 + 96] }/(12)
x₁;x₂ = { -5 ± √[121] }/(12)
x₁;x₂ = { -5 ± 11 }/(12)
Primera solución
x1 = (-5 - 11)/12 = -16/12
x1 = -4/3
************
Segunda solución
x2 = (-5 + 11)/12 = 6/12
x2 = 1/2
************
Verificado
¿No te sale qué?
¿Acaso tienes las respuestas?
Ni **** idea