Se considera un triángulo isósceles rectángulo cuyos catetos miden 10m.
Halla la medida del perímetro y del área del triángulo me me explican paso a paso por fa
Hola
hip^2 = cat^2 + cat^2 = 2 cat^2
entonces
hip = raiz(2) * cat = 1.414.. * 10 m = 14.14 m
perimetro = 10 m + 10 m + 14.14.. m = 34.14... m
area = (1/2) * 10 m * 10 m = 50 m^2
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Hola
hip^2 = cat^2 + cat^2 = 2 cat^2
entonces
hip = raiz(2) * cat = 1.414.. * 10 m = 14.14 m
perimetro = 10 m + 10 m + 14.14.. m = 34.14... m
area = (1/2) * 10 m * 10 m = 50 m^2