Verified answer

This is Gibbs free energy equation. It relates Entropy (dS) and Enthalpy (dH), where dG = dH-T*dS. Where d is delta, and T is temperature. This is assuming temperature (in Kelvin) is constant. It also exists for a reaction given a K value: dG = -R*T*ln(K) (OR -2.303*R*T*log(Kequilibrium)). To find the specific free energy of a reaction at equilibrium, we have dG = dGo+R*T*ln(Q) where dGo is the dG at ideal conditions (25C and 1 atm).

Note that you can also find Kequilibrium by the equation: Keq=e^((-dGo)/(R*T))

Good luck with Finals! Mine are next week...