-5(x-5)^2=500
:-
Assuming that should be shown as :-
5 ( x - 5 )² = 500
( x - 5 )² = 100
x - 5 = ± 10
x. = - 5 , 15
-5(x-5)^2=500. Dividing by -5 each side gives:
(x-5)² = -100. Taking the root each side gives
(x-5) = ±√(-100) = ±√100 √(-1) = ±10 * i. Add 5 each side gives your two answers. Done!
For -5(x-5)^2=500 the answer is:
x=5+10i, 5-10i
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Answers & Comments
:-
Assuming that should be shown as :-
5 ( x - 5 )² = 500
( x - 5 )² = 100
x - 5 = ± 10
x. = - 5 , 15
-5(x-5)^2=500. Dividing by -5 each side gives:
(x-5)² = -100. Taking the root each side gives
(x-5) = ±√(-100) = ±√100 √(-1) = ±10 * i. Add 5 each side gives your two answers. Done!
For -5(x-5)^2=500 the answer is:
x=5+10i, 5-10i