Given two lines: 3x−5y+9 = 0 and 2x+6x−3 = 0. Determine the intersection point between the two.?
Given two lines: 3x−5y+9 = 0 and 2x+6x−3 = 0. Determine the intersection point between the two.
Update:No actually it's 6x and that's why I couldn't solve it :|
Update 3:No actually it's 6x and that's why I couldn't solve it :|
More Questions From This User See All
Answers & Comments
Verified answer
3X-5Y=0
-3X......-3X (subtract 3X from both sides)
-5Y=-3X+0
/-5.../-5.../-5 (divide everything by 5)
Y=3/5X+0
2X+6X-3=0
..i think you meant to put 6Y?
2X+6Y-3=0
-2X...........-2X (subtract both sides by 2X)
6Y-3=-2X+0
....+3.......+3 (add 3 to both sides)
6Y=-2X+3
/6...../6.../6 (divide everything by 6)
Y=-1/3X+1/2
..the intersection is X: .54 Y: .32
CRAP lol lemme try it
2X+6X-3=0
8X-3=0
...+3..+3
8X=3
/8../8
X=3/8 ?
crap idk lol try substitution? sorry :c
Rewrite the two equations a million.) y = 4/3x -4 2.) y = 4/3x +3 Write the equation for the line it is perpendicular to the 1st equation 3.) y = -3/4x -4 Now set equation 3.) equivalent to equation 2.) and which will locate the factor on the 2d line it is perpendicular to the y intercept of the 1st line. -3/4x - 4 = 4/3x + 3 resolve for x -3/4x -4 - 4/3x -3 = 0 -9/12x - sixteen/12x -7 = 0 -25/12 x = 7 x = - 7*12/25 or -3.36 stick that lower back in the two equation 2.) or 3.) and resolve for y y = 4/3x +3 y = -a million.40 8 next use the gap formula for (0 , -4) and (-3.36, -a million.40 8) D = sqrt [(-3.36-0)^2 + (-a million.40 8- -4)^2] answer is 4.2