If the angle is in the third Quadrant, we can say that...
cos(t) < 0
sin(t) < 0
So?
cos(t) = -√(1 - sin²(t))
= -√(1 - (-5/6)²)
= -√(36/36 - 25/36)
= -√(11)/6
Good luck!
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Verified answer
If the angle is in the third Quadrant, we can say that...
cos(t) < 0
sin(t) < 0
So?
cos(t) = -√(1 - sin²(t))
= -√(1 - (-5/6)²)
= -√(36/36 - 25/36)
= -√(11)/6
Good luck!