hope thats not confusing.
[ f(x+Δx) - f(x) ] / Δx
[ (2 - 3 (x + Δx)^2 ) - (2 - 3x^2) ] / Δx
[ (2 - 3 (x^2 + 2x Δx + (Δx)^2 ) - (2 - 3x^2) ] / Δx
[ (2 - 3x^2 - 6x Δx - 3(Δx)^2 - 2 + 3x^2 ] / Δx
[ - 6x Δx - 3(Δx)^2 ] / Δx
- 6x- 3Δx. . . . .Δx--->0
- 6x- 3*0
-6x
=========
free to e-mail if have a question
Do you have to show it longhand according to the definition?
Or can you just use the power rule?
f'(x) = -6x
power rule w/ lim applied
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Verified answer
[ f(x+Δx) - f(x) ] / Δx
[ (2 - 3 (x + Δx)^2 ) - (2 - 3x^2) ] / Δx
[ (2 - 3 (x^2 + 2x Δx + (Δx)^2 ) - (2 - 3x^2) ] / Δx
[ (2 - 3x^2 - 6x Δx - 3(Δx)^2 - 2 + 3x^2 ] / Δx
[ - 6x Δx - 3(Δx)^2 ] / Δx
- 6x- 3Δx. . . . .Δx--->0
- 6x- 3*0
-6x
=========
free to e-mail if have a question
Do you have to show it longhand according to the definition?
Or can you just use the power rule?
f'(x) = -6x
power rule w/ lim applied