y = -8 + 5√(5x - 1)
y + 8 = 5√(5x - 1)
(y + 8)/5 = √(5x - 1)
(y + 8)²/25 = (5x - 1)
(y + 8)²/25 + 1 = 5x
(y² + 16y + 64)/25 + 25/25 = 5x
(y² + 16y + 89)/125 = x
f ֿ¹ (x) = (x² + 16x + 89)/125
f (x) = -8 + 5â(5x â 1)
x = -8 + 5â(5y â 1)
x + 8 = 5â(5y â 1)
â(5y â 1) = (x + 8)/5
5y â 1 = (x + 8)²/25
5y = (x + 8)²/25 + 1
y = (x + 8)²/125 + 5
y = (x² + 16x + 64 + 625)/125
f ֿ¹ (x) = (x² + 16x + 689)/125
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Verified answer
y = -8 + 5√(5x - 1)
y + 8 = 5√(5x - 1)
(y + 8)/5 = √(5x - 1)
(y + 8)²/25 = (5x - 1)
(y + 8)²/25 + 1 = 5x
(y² + 16y + 64)/25 + 25/25 = 5x
(y² + 16y + 89)/125 = x
f ֿ¹ (x) = (x² + 16x + 89)/125
f (x) = -8 + 5â(5x â 1)
x = -8 + 5â(5y â 1)
x + 8 = 5â(5y â 1)
â(5y â 1) = (x + 8)/5
5y â 1 = (x + 8)²/25
5y = (x + 8)²/25 + 1
y = (x + 8)²/125 + 5
y = (x² + 16x + 64 + 625)/125
f ֿ¹ (x) = (x² + 16x + 689)/125