how do you prove that all equilateral triangles have an altitude ( line from one vertex, or point, to the opposite side forming a perpendicular angle) that is the perpendicular bisector of the opposite side. aka the line hits the midpoint of the opposite side and forms a perpendicular angle.
plzzz plzz plzz answer. its a take home test and i have no clue :(
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domi, equi tris form perp ∠ -that hits opp side midpt- by perp ∠ def