Calcule o comprimento das medidas de um triangulo de vértice A (2,-6) B(-4,2) e C(0,4)
√(-4-2)²+(2+6)=
√36+64=
√100=10
√(0+4)²+(4-2)²=
√16+4=2√5
√(2-0)²+(-6-4)²=
√4+100=
√104=2√26
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Verified answer
√(-4-2)²+(2+6)=
√36+64=
√100=10
√(0+4)²+(4-2)²=
√16+4=2√5
√(2-0)²+(-6-4)²=
√4+100=
√104=2√26