Formic acid is a weak monoprotic acid with Ka = 1.8×10-4 M. Calculate [H3O+] in a 2.81×10-1 M solution of sodi?
Formic acid is a weak monoprotic acid with Ka = 1.8×10-4 M. Calculate [H3O+] in a 2.81×10-1 M solution of sodium formate.
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Equation:
Ka = [H+] [HCOO-] /[HCOOH]
You want [H+]
You know Ka , you know [HCOOH] and [H+] = [HCOO-]
substitute and solve for [H+]
1.8*10^-4 = [H+]² / (2.81*10^-1)
[H+]² = (1.8*10^-4) *( 2.81*10^-1)
[H+]² = 5.058*10^-5
[H+] = 7.1*10^-3M
[H3O+] = 7.1*10^-3M