For the reaction 2 S + 3 O2 → 2 SO3 , what is the maximum amount of SO3 which could be formed from 4.04 g of S?
For the reaction
2 S + 3 O2 → 2 SO3 ,
What is the maximum amount of SO3 which
could be formed from 4.04 g of S and 13.64 g
of O2? Answer in units of g
These were all of my tries:
Try#1: 7.566023207
12/13/13 4:18 PM
Try#2: .189375
12/13/13 4:49 PM
Try#3: .3779232
12/13/13 4:52 PM
Try#4: 7.564701598
12/13/13 5:29 PM
Try#5: .18896
12/13/13 5:32 PM
Try#6: 6.72499
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Verified answer
Convert the amount of sulfur (S) into moles:
4.04 g / 32.065 g/mol = 0.126 mol
Convert the amount of oxygen (O2) into moles:
13.64 g / (15.999*2) g/mol = 0.426 mol
Notice the multiplier of 2, which we need because there are 2 oxygen atoms per molecule of O2.
For every 1 mole of sulfur (S), we need 1.5 moles of oxygen (O2) to form 1 mole of SO3. As calculated, we have:
0.126 mol of S
0.426 mol of O2
Given this information and the 1:1.5 ratio, we see that sulfur is the limiting reactant. Therefore, 0.126 moles is the maximum quantity of SO3 we can produce.