For t is greater or equal to 0 v(T)=2T-5sinπT at t=o the particle is located at t=0?
A) write an expression for the acceleration a(t) of the particle
B) write an expression for the position x(t) of the particle
C) For what values of t (t is greater than or less than 0) is the particle moving left?
D) For t less than 1 find the position of the particle the first time the velocity of the particle is zero
HELP plz
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a) differentiate v(t)
b) integrate v(t) using the boundary condition that x = 0 when t = 0
c) when the expression for v<0, or when 2T< 5 sin pi T
d) set v = 0 which means 2 t = 5 sin (pi t)
the easiest way to solve this might be graphically, plot the two functions and see where they intersect;
I get t = 0.885s