Verified answer

this is a [ π { (large radius² - small radius² } thickness ] concept

large radius is [ 7y - 0 ] , small is [ y³ - 0 ] , thickness is [ dy ] , y in [ 0 , √7 ]

you can certainly do the integration

this would in all danger be deleted via fact its no longer a query yet heck with it. use your information of the quantity of a cylinder and take a slice out of the regiond192e0c4ad64a9c35fe32972477e4cd8 radius could be yd192e0c4ad64a9c35fe32972477e4cd8 or x^2+3. on an identical time as the thickness is dx dV= (pi)(x^2+3)^2 dx V= int[d192e0c4ad64a9c35fe32972477e4cd8d192e0c4ad64a9c35fe32972477e4cd8d192e0c4ad64a9c35fe32972477e4cd8] (pi)(x^2+3)^2 dx