Find the slope of the curve defined by f(x)=x^3 sinx at x=π.
f(x) = x^3 sin x
f ' (x) = 3x^2 sin x + x^3 cos x
f ' (pi) = 3pi*2 (0) + pi^3 (-1) = -pi^3
f ' (pi) = slope of curve at x = pi ==> -pi^3
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f(x) = x^3 sin x
f ' (x) = 3x^2 sin x + x^3 cos x
f ' (pi) = 3pi*2 (0) + pi^3 (-1) = -pi^3
f ' (pi) = slope of curve at x = pi ==> -pi^3