Sin is bad
11pi/2 = [(12-1)/2]pi = 3(2pi) - (pi/2). Now 3(2pi) is co-terminal with 0 so 11pi/2 is co-terminal
with - (pi/2) and sin(11pi/2) = sin(-pi/2) = -sin(pi/2) = -1.
11π/2 = 3π/2 + 2·2π
sin(11π/2) = sin(3π/2)
refer to the unit circle
sin(3π/2) = -1
11π / 2 = 4π/2 + 4π/2 + 3π/2 = 2π + 2π + 3π/2 which is two full rotations plus 3π/2
and sin 3π/2 = -1 so sin 11π/2 also = -1
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Sin is bad
11pi/2 = [(12-1)/2]pi = 3(2pi) - (pi/2). Now 3(2pi) is co-terminal with 0 so 11pi/2 is co-terminal
with - (pi/2) and sin(11pi/2) = sin(-pi/2) = -sin(pi/2) = -1.
11π/2 = 3π/2 + 2·2π
sin(11π/2) = sin(3π/2)
refer to the unit circle
sin(3π/2) = -1
11π / 2 = 4π/2 + 4π/2 + 3π/2 = 2π + 2π + 3π/2 which is two full rotations plus 3π/2
and sin 3π/2 = -1 so sin 11π/2 also = -1