One ways is to find the normal to the plane; this can be found via the cross of the two vectors representing the directions of the two lines. Once this normal found, use the point [0,0,0] to find the equation of the plane.
Or, find three (non collinear) points of the plane; One is already explicitly given. Take another form a line and another from the other line. From these points, plug them each into
ax + by +cz = 1 and solve for a,b &c.
Done!
Show your steps here if need be and we can take it from there.
Hopefully no one will spoil you the answer thereby depriving you from your personal enhancement; that would be very inconsiderate of them.
Answers & Comments
There are many ways to do this.
One ways is to find the normal to the plane; this can be found via the cross of the two vectors representing the directions of the two lines. Once this normal found, use the point [0,0,0] to find the equation of the plane.
Or, find three (non collinear) points of the plane; One is already explicitly given. Take another form a line and another from the other line. From these points, plug them each into
ax + by +cz = 1 and solve for a,b &c.
Done!
Show your steps here if need be and we can take it from there.
Hopefully no one will spoil you the answer thereby depriving you from your personal enhancement; that would be very inconsiderate of them.