Find the equation in standard form which passes through (3, –6) and (–2, –1). You must show all work.?
Why must I show all work? Perhaps you have to show all work to get credit for the homework, but that doesn't mean I have to.
The equation in standard form is: x + y = -3
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Hi. To get this you need to know the slope and the y intercept.
The slope is gotten through subtracting y2-y1 and dividing that by x2-x1.
so -1- (-6) / -2 -3 = 5/-5 = -1
so you have y= -1x + b
To get b you can plug in one of the coordinates such as (-2, -1)
-1= -1(-2) +b
-1= 2 +b
-1-2 =b
b= -3
Putting b into the equation: y= -x -3
I think thats correct. Please recheck your problem too.
slope = (-1 + 6)/(-2 - 3) = 5/-5 = -1
Eqn of line:
y + 6 = -1(x - 3)
y = -x - 3
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Why must I show all work? Perhaps you have to show all work to get credit for the homework, but that doesn't mean I have to.
The equation in standard form is: x + y = -3
...
Hi. To get this you need to know the slope and the y intercept.
The slope is gotten through subtracting y2-y1 and dividing that by x2-x1.
so -1- (-6) / -2 -3 = 5/-5 = -1
so you have y= -1x + b
To get b you can plug in one of the coordinates such as (-2, -1)
-1= -1(-2) +b
-1= 2 +b
-1-2 =b
b= -3
Putting b into the equation: y= -x -3
I think thats correct. Please recheck your problem too.
slope = (-1 + 6)/(-2 - 3) = 5/-5 = -1
Eqn of line:
y + 6 = -1(x - 3)
y = -x - 3