CFCl3 = 137.3681 g/mol
n / V = P / RT = (7.59 atm) / ((0.082057338 L atm/K mol) x (181 + 273) K) = 0.2037 mol/L
(137.3681 g/mol) x (0.2037 mol/L) = 28.0 g/L
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CFCl3 = 137.3681 g/mol
n / V = P / RT = (7.59 atm) / ((0.082057338 L atm/K mol) x (181 + 273) K) = 0.2037 mol/L
(137.3681 g/mol) x (0.2037 mol/L) = 28.0 g/L