Verified answer

f(x) = 3x − 4

y = 3x - 4

x = 3y - 4

x + 4 = 3y

.........x + 4

y = -----------------

............3

..............x + 4

f⁻¹(x) = ------------- answer//

...............3

Let y=3x-4

Interchange x and y

x=3y-4

solve for y

3y=x+4

y=(x+4)/3

f^-1(x)= (x+4)/3

Let y = 3x - 4

Interchange x and y.....which reflects the function in the line y = x

=> x = 3y - 4

i.e. y = f^-1(x) = (x + 4)/3

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y = 3x - 4 --> solve for x

y + 4 = 3x

(y + 4) / 3 = x --> now replace the "y" with x .

f^-1 (x) = (x + 4) / 3

y = 3x - 4

change x's and y's and solve for y then determine if a restriction is on the new domain

x = 3y - 4

x + 4 = 3y

(x + 4)/3 = y

domain is all reals