Find an expression for a cubic function f if f(1) = 24 and f(−5) = f(0) = f(2) = 0.1) f(x) =. Created by Janet. science-mathematics-en - mathematics-en

f(x) = Ax(x+5)(x-2)24 = -6Af(x) = -4x(x+5)(x-2)

Find an expression for a cubic function f if f(1) = 24 and f(−5) = f(0) = f(2) = 0.?

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Find an expression for a cubic function f if f(1) = 24 and f(−5) = f(0) = f(2) = 0.?

Find an expression for a cubic function f if f(1) = 24 and

f(−5) = f(0) = f(2) = 0.

1) f(x) =

-5, 0, and 2 are zeros.

That means that (x + 5), (x - 0) and (x - 2) are factors.

So f(x) = a(x + 5)(x)(x - 2) for some real number a.

Now plug in x = 1 and f(x) = 24 to solve for a.