7 • 40 = 280
280 - 8y = 32
-8y = 32 - 280 = -248
y = -248 ÷ -8 = 31
Slope of original line = 7/8 so slope of perpendicular = its opposite reciprocal, -8/7
Point slope form: y - 31 = -8/7(x - 40)
7y - 217 = -8(x - 40)
7y - 217 = -8x + 320
8x + 7y = 320 + 217
8x + 7y = 537 (standard form)
7y = -8x + 537
y = -8/7 x + 537/7
g(x) = -8/7 x + 537/7 (function form)
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Answers & Comments
7 • 40 = 280
280 - 8y = 32
-8y = 32 - 280 = -248
y = -248 ÷ -8 = 31
Slope of original line = 7/8 so slope of perpendicular = its opposite reciprocal, -8/7
Point slope form: y - 31 = -8/7(x - 40)
7y - 217 = -8(x - 40)
7y - 217 = -8x + 320
8x + 7y = 320 + 217
8x + 7y = 537 (standard form)
7y = -8x + 537
y = -8/7 x + 537/7
g(x) = -8/7 x + 537/7 (function form)