Verified answer

1. 3a²+6ab-24b² = 3(a^2+2ab-8b^2) = 3(a+4b)(a-2b)

2. 7a²-28b² = 7(a^2-4b^2) = 7(a+2b)(a-2b)

3. 4a²+14ab+12b² = 2(2a^2+7ab+6b^2) = 2(2a+3)(a+2)

4. a^3-4a²b-21ab² = a(a^2-4ab-21b^2) = a(a-7b)(a+3b)

5. a^3-ab^3 = a(a^2-b^3)

Your answer will be something like this:

(#a + #b)(#a + #b)

That way, you're getting both a times a, b times b, and a times b.

Hope this helps somewhat.

1) (3a+or- ___)*(a+or-___)

(__+or- 6b) * (__+or- 4b)

(3a-6b)(a+4b)

You should be able to use the same way you factor a normal equation ax^2+bx+c.

go to www.cramster.com

Find your math book

And look at examples from there!

hope this helps!

Liz