Verified answer

You can can first factor x out of the equation:

x^3 - 26 x^2 + 48x = x (x^2 - 26x

+48)

Then you can use the quatratic formula.

For the other equations basically you want to find what is common among each of the variables and then factor that out.

x3 – 26x2 + 48x

= x(x^2-26x+48)

= x(x-24)(x-2)

x2 – 6wy + 3xy – 2wx

= x(x+3y)-2w(x+3y)

= (x-2w)(x+3y)

you shouldn't ask people to do your homework for you.

I'll tell you how to do the first one only, though

you first factor out 1 x so you get

x^2-26x+48

then you use the quadratic formula...which is for ax^2+bx+c.....(-b+or- the square root of (b^2-4ac)) all over 2a

anyways, once you do all of that work...you get x=2,24 you then must make them equal to zero...so you get (x-2)(x-24)=0...now dont forget the x you took out earlier so...x(x-2)(x-24) is the complete factor.

your turn :D!

x(x^2 - 26x + 48) = x(x-24)(x-2)

x^2 + 3xy - 6wy - 2wx = x(x+3y) - 2w(3y+x) = (x-2w)(x+3y)

(x-7)(x+2)

(2x-6y)(2x+6y)

(3x+4)(x-2)

2(12x^2+5x-2) = 2(3x+2)(4x-1)