Verified answer

We can use Charles's Law equation:

(Volume 1) / (Temperature 1) = (Volume 2) / (Temperature 2)

Note: Celsius temperatures have to be converted to Kelvins.

Volume 2 = [(Volume 1)(Temperature 2)] / (Temperature 1)

Volume 2 = [(5.00 L)(373 K)] / (223 K)

Volume 2 = 8.3632286 L or 8.36 L rounded to three significant figures

Answer: When exactly 5.00 L of air at –50°C is warmed to 100.0°C, the new volume is about 8.36 L if the pressure remains constant.

Use v1/t1 = v2/t2, it works because everything else stays constant.

Ahem, and temperature in Kelvin too. (Celsius +237 to get kelvin)

5/223 = v2/373

v2=8.36