Evaluate the function f(x) = √(-2x + 3), find f(-3)?
Sol f(x) = √(-2x + 3)
f(-3)=√(-2(-3) + 3)
f(-3)=√(6 + 3)
= 3 ................Ans
+3
+3 and -3
+- 3
f (-3) = ± â 9 = ± 3
F(-3) =sqrt[-2(-3) +3] = sqrt(6+3) =sqrt9 =3
Plug in -3 where you see x.
f(x) = sqrt(-2x + 3)
f(-3) = sqrt(-2(-3) + 3)
f(-3) = sqrt(6 + 3)
f(-3) = sqrt(9)
f(-3) = ±3
f(-3) = â(-2(-3) + 3)
f(-3) = â(6 + 3)
f(-3) = â9
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Verified answer
Evaluate the function f(x) = √(-2x + 3), find f(-3)?
Sol f(x) = √(-2x + 3)
f(-3)=√(-2(-3) + 3)
f(-3)=√(6 + 3)
= 3 ................Ans
+3
+3 and -3
+- 3
f (-3) = ± â 9 = ± 3
F(-3) =sqrt[-2(-3) +3] = sqrt(6+3) =sqrt9 =3
Plug in -3 where you see x.
f(x) = sqrt(-2x + 3)
f(-3) = sqrt(-2(-3) + 3)
f(-3) = sqrt(6 + 3)
f(-3) = sqrt(9)
f(-3) = ±3
f(-3) = â(-2(-3) + 3)
f(-3) = â(6 + 3)
f(-3) = â9
f(-3) = ±3