Evaluate Cos(5,555,555π/2) by using the period of the function? please help! ?
how do i evaluate
cos(5,555,555π/2) using the period of the function?
please explain!
thanks :)!
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how do i evaluate
cos(5,555,555π/2) using the period of the function?
please explain!
thanks :)!
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Verified answer
note:
cos(π/2) = 0
cos(3π/2) = 0
the period of cosine is 2π
then
cos(π/2 + 2kπ) = 0 ... for whatever integer k
and cos(3π/2 + 2kπ) = 0 ... for whatever integer k
thus
cos(kπ + π/2) = 0 ... for whatever integer k .
thus
cos(5,555,555π/2) = 0