Encuentre el valor de x que satisface la siguiente ecuaciΓ³n trigonomΓ©trica para Γ‘ngulos entre 0Β°β€ x β€ 360Β° ππͺππ^π(π) πͺππ(π)βπ=π?
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Do you mean ππͺππ^π(π) + πͺππ(π)βπ=π ?
If so, let u=cos(x), so that
3^2 + u - 2 = 0
(3u-2)(u+1) = 0
u=-1 or u=2/3
since u=cos(x), conclude that
x=180Β° or x=arccos(2/3) = 48.19Β° or 360Β°-48.19Β°.