e^3√x+1 Thanks!
.................. ......... 3.____
Do you mean e^V(x-1) ?
This is e^(x-1)^(1/3) = e^u
The derivative is e^u u'
u = (x-1)^1/3
The derivative is (1/3)e^ (1/3-1) = 1/[3 (x-1)^(2/3)]
Remember that a ^2/3 = cube root of a^2
Ana
(e)'(cubed root of x+1)+(e)(1/3*(1/(-cubed root of x+1)^2))
0+1/3e(1/((cubed root of x+1)^2))
lol very confusing but i hope it helps
y = e3âx+1
ln y = (x+1)^(1/3)
Differentiating implicitely
(1/y) dy/dx = (1/3)(x+1)^(-2/3)
dy/dx = (y/3)*(x+1)^(-2/3)
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Verified answer
.................. ......... 3.____
Do you mean e^V(x-1) ?
This is e^(x-1)^(1/3) = e^u
The derivative is e^u u'
u = (x-1)^1/3
The derivative is (1/3)e^ (1/3-1) = 1/[3 (x-1)^(2/3)]
Remember that a ^2/3 = cube root of a^2
Ana
(e)'(cubed root of x+1)+(e)(1/3*(1/(-cubed root of x+1)^2))
0+1/3e(1/((cubed root of x+1)^2))
lol very confusing but i hope it helps
y = e3âx+1
ln y = (x+1)^(1/3)
Differentiating implicitely
(1/y) dy/dx = (1/3)(x+1)^(-2/3)
dy/dx = (y/3)*(x+1)^(-2/3)