Verified answer

3! = 6

I'll have to look into it, but I don't think there is a convention for order precedence regarding factorials. The question should have been with brackets to make it explicitly clear.

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Actually I was wrong, according to this http://oeis.org/wiki/Operator_precedence factorials proceed exponents.

Thus

sqrt 9! => (9!)^(1/2) => 72 sqrt(70)

Assuming the factorial is outside the root, then yes you apply the square root first.

[√(9)] !

3!

3*2*1 = 6

3!

6

square root the 9 first

Assuming you're using square root the answer is 3 because 3 x 3 equals 9

3 square root of 9 is three because 3*3=9

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