determine whether the function f(x) = 1 - |x| is differentiable at x = 0 by considering lim h→0 {f (0+h) - f (0)}/h
Suppose that h ≥ 0. Then:
[f(0+h) - f(0)]/h = [(1 - |h|) - 1]/h = -h/h = -1.
On the other hand, if h < 0,
[f(0+h) - f(0)]/h = [(1 - |h|) - 1]/h = h/h = 1.
The left-hand limit and the right-hand limit will never agree at 0.
Not differentiable..draw the graph and check
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Verified answer
Suppose that h ≥ 0. Then:
[f(0+h) - f(0)]/h = [(1 - |h|) - 1]/h = -h/h = -1.
On the other hand, if h < 0,
[f(0+h) - f(0)]/h = [(1 - |h|) - 1]/h = h/h = 1.
The left-hand limit and the right-hand limit will never agree at 0.
Not differentiable..draw the graph and check