X=? y=0
x=0 y=?
x=1 y=?
x=? y=3
By substituting the values into 8x-4y = 18
x = 2.25 when y = 0
x = 0 when y = -4.5
x = 1 when y = -2.5
x = 3.75 when y = 3
:--
8x - 4y = 18
( 9/4 , 0 ) , ( 0 , - 9/2 ) , ( 1 , -5/2 ) , ( 15/4 , 3 )
I'll do the first one. You can do the others from there following the same steps:
You are told that y = 0 and need to solve for x. So substitute the value and solve for the unknown:
8x - 4(0) = 18
8x - 0 = 18
8x = 18
x = 18/8
x = 9/4
Now do the same with the other three.
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Answers & Comments
By substituting the values into 8x-4y = 18
x = 2.25 when y = 0
x = 0 when y = -4.5
x = 1 when y = -2.5
x = 3.75 when y = 3
:--
8x - 4y = 18
( 9/4 , 0 ) , ( 0 , - 9/2 ) , ( 1 , -5/2 ) , ( 15/4 , 3 )
I'll do the first one. You can do the others from there following the same steps:
8x - 4y = 18
You are told that y = 0 and need to solve for x. So substitute the value and solve for the unknown:
8x - 4(0) = 18
8x - 0 = 18
8x = 18
x = 18/8
x = 9/4
Now do the same with the other three.