Derivatives f(x) = 1/x² ; a =1?
a) For the following function and points , find f ' (a)
b) Determine an equation of the line tangent to the graph of f at (a, f(a)) for the given value of a.
f(x) = 1/x² ; a =1
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f(x) = 1/x² = x^(-2)
f'(x) = -2x^(-3)
f'(1) = -2
f(1) = 1
Equation of tangent line: y = f'(a)(x - a) + f(a)
y = -2(x - 1) + 1
y = -2x + 3