derivative function: ƒ(x) = x²e×?
Please help me out with this too ƒ(x) = 1 / x - 5
ƒ(x) = x³ + x / x² - 4
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Please help me out with this too ƒ(x) = 1 / x - 5
ƒ(x) = x³ + x / x² - 4
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f'(x) = 2x * e^x + e^x * x^2
f'(x) = xe^x(2 + x)
f'(x) = -1 / (x - 5)^2
f'(x) = [(3x^2 + 1)(x^2 - 4) - (2x)(x^3 + x)] / (x^2 - 4)^2