Normalidad=moles soluto/1L disolución
0.5=moles soluto /0.5L
mol=0.5*0.5L=0.25
0.25mol*40g/mol=10g
1 mol de NaOH = 40 g
1 N -------------------- 40 g/l
0,5 N ---------------- 0,5*40/1 = 20 g/l
en 1.000 ml -------------- 20 g
en 500 ml ------------- 500*20/1.000 = 10 g
10g
N = M (para el NaOH)
M = n/V
n = M * V
n = 0.5mol/L * 0.5L = 0.25mol
1 mol son 40g
entonces 0.25mol son 10g
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Verified answer
Normalidad=moles soluto/1L disolución
0.5=moles soluto /0.5L
mol=0.5*0.5L=0.25
0.25mol*40g/mol=10g
1 mol de NaOH = 40 g
1 N -------------------- 40 g/l
0,5 N ---------------- 0,5*40/1 = 20 g/l
en 1.000 ml -------------- 20 g
en 500 ml ------------- 500*20/1.000 = 10 g
10g
N = M (para el NaOH)
M = n/V
n = M * V
n = 0.5mol/L * 0.5L = 0.25mol
1 mol son 40g
entonces 0.25mol son 10g