cual seria la ecuacion que corresponde a esta grafica?
Figura girada 90º a izquierda...
Ahora me doy cuenta...
m = (-2-1)/(0 - 4) = -3/-4 = 3/4
y - (-2) = m (x - 0)
y + 2 = (3/4) x
y = -2 + (3/4) x
**********************
l
https://www.youtube.com/watch?v=Y5zCUpQy6Rw
How do I find the equation for the straight line with two points A (0 ; - 2) and B (4 ; 1) ?
The typical equation of a line is: y = mx + b → where m: slope and where b: y-intercept
To calculate m
m = (yB - yA) / (xB - xA) = (1 + 2) / (4 - 0) = 3/4
The equation of the line becomes: y = (3/4).x + b
To calculate b
The line passes through A, so the coordinates of this point must verify the equation of the line.
y = (3/4).x + b
b = y - (3/4).x → you substitute x and y by the coordinates of the point A (0 ; - 2)
b = - 2 - [(3/4) * 0] = - 2
→ The equation of the line is: y = (3/4).x - 2
¿Porque nosotros tenemos que hacer eso si te lo dieron a vos?
Buena suerte a todos, espero que esten bien, porfavor ayudenme a crecer a mi canal y suscribanse, les aseguro que les sacare una sonrisa
https://www.youtube.com/channel/UCM39NSa2hHPtAd7TO...
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Verified answer
Figura girada 90º a izquierda...
Ahora me doy cuenta...
m = (-2-1)/(0 - 4) = -3/-4 = 3/4
y - (-2) = m (x - 0)
y + 2 = (3/4) x
y = -2 + (3/4) x
**********************
l
https://www.youtube.com/watch?v=Y5zCUpQy6Rw
How do I find the equation for the straight line with two points A (0 ; - 2) and B (4 ; 1) ?
The typical equation of a line is: y = mx + b → where m: slope and where b: y-intercept
To calculate m
m = (yB - yA) / (xB - xA) = (1 + 2) / (4 - 0) = 3/4
The equation of the line becomes: y = (3/4).x + b
To calculate b
The line passes through A, so the coordinates of this point must verify the equation of the line.
y = (3/4).x + b
b = y - (3/4).x → you substitute x and y by the coordinates of the point A (0 ; - 2)
b = - 2 - [(3/4) * 0] = - 2
→ The equation of the line is: y = (3/4).x - 2
¿Porque nosotros tenemos que hacer eso si te lo dieron a vos?
Buena suerte a todos, espero que esten bien, porfavor ayudenme a crecer a mi canal y suscribanse, les aseguro que les sacare una sonrisa
https://www.youtube.com/channel/UCM39NSa2hHPtAd7TO...