Solve For Θ
0 ≤ Θ < 360
csc²Θ - 6 = cscΘ
let cscΘ = x
x² - 6 = x
x² - x - 6 = 0
factoring:
(x - 3)(x + 2) = 0
so
x = 3
or
x = -2
plugging back in cscΘ = x
cscΘ = 3
cscΘ = -2
cscΘ = 1/(sinΘ)
1/(sinΘ) = 3
1/(sinΘ) = -2
sinΘ = 1/3
sinΘ = -1/2
Θ = arcsin (1/3) = 19.5 degrees
Θ = arcsin (-1/2) = 330 degrees
or 1/sin^2Θ - 6 = 1/Sin Θ
or1-6Sin^2 Θ - SinΘ =0
or 6Sin^2 Θ +SinΘ -1 =0
or 6 Sin^2Θ +3SinΘ -2sinΘ -1=0
or 3SinΘ(2SinΘ + 1) - 1(2SinΘ + 1)=0
or (3SinΘ -1)(2SinΘ + 1) = 0
so Θ=Sin-1(1/3) or Θ= Sin-1(-1/2)
so Θ = 19.3 + 2n*pi deg or Θ = 330 + 2n*pi deg
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Answers & Comments
Verified answer
csc²Θ - 6 = cscΘ
let cscΘ = x
x² - 6 = x
x² - x - 6 = 0
factoring:
(x - 3)(x + 2) = 0
so
x = 3
or
x = -2
plugging back in cscΘ = x
cscΘ = 3
or
cscΘ = -2
cscΘ = 1/(sinΘ)
1/(sinΘ) = 3
or
1/(sinΘ) = -2
sinΘ = 1/3
or
sinΘ = -1/2
Θ = arcsin (1/3) = 19.5 degrees
or
Θ = arcsin (-1/2) = 330 degrees
or 1/sin^2Θ - 6 = 1/Sin Θ
or1-6Sin^2 Θ - SinΘ =0
or 6Sin^2 Θ +SinΘ -1 =0
or 6 Sin^2Θ +3SinΘ -2sinΘ -1=0
or 3SinΘ(2SinΘ + 1) - 1(2SinΘ + 1)=0
or (3SinΘ -1)(2SinΘ + 1) = 0
so Θ=Sin-1(1/3) or Θ= Sin-1(-1/2)
so Θ = 19.3 + 2n*pi deg or Θ = 330 + 2n*pi deg
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