(cot^2θ)/(csc^2θ)+(tan^2θ)/(sec^2θ) = 1?
(cot^2θ)/(csc^2θ)+(tan^2θ) / (sec^2θ) = 1?
I think I got this one. Thanks everyone for helping me out. I just want to make sure I did this one right, because it took a long time to simplify, and maybe I did something wrong that could have made it easier.
Thanks again, I thought I never would get this stuff!
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(cot^2θ)/(csc^2θ)+(tan^2θ) / (sec^2θ) = 1
cot^2θ = cos^2θ/sin^2θ
csc^2θ = 1//sin^2θ
tan^2θ = sin^2θ/cos^2θ
sec^2θ = 1/cos^2θ
(cos^2θ/sin^2θ)(sin^2θ)+(sin^2θ/cos^2θ)(cos^2θ)=1
cos^2θ+sin^2θ=1
The first term if you simplyfy it will be cos^2 theta & second term will be Sin^2 theta Then their sum will be obiviously 1
u got it