resolvam no intervalo de 0 ≤ x ≤2pi.
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cos(2x) = cos²(x) - sen²(x)
cos²(x) - sen²(x) + sen²(x) + cos(x) = 0
cos²(x) + cos(x) = 0
cos(x)*(cos(x) + 1) = 0
cos(x) = 0 ---> x = pi/2 ou x = 3pi/2
cos(x) + 1 = 0
cos(x) = -1 --> x = pi
pronto
Cos2x+sen²x+cosx=
Cos²x-Sen²x+sen²x+cosx
cos²x+cosx
cosx(cosx+1)=0
cosx=0 --> 90 graus
cosx+1=-1 --> 180 graus
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Verified answer
cos(2x) = cos²(x) - sen²(x)
cos²(x) - sen²(x) + sen²(x) + cos(x) = 0
cos²(x) + cos(x) = 0
cos(x)*(cos(x) + 1) = 0
cos(x) = 0 ---> x = pi/2 ou x = 3pi/2
cos(x) + 1 = 0
cos(x) = -1 --> x = pi
pronto
Cos2x+sen²x+cosx=
Cos²x-Sen²x+sen²x+cosx
cos²x+cosx
cosx(cosx+1)=0
cosx=0 --> 90 graus
cosx+1=-1 --> 180 graus