How do you do this?
Polar: (r, Θ)
Rectangular: (x, y)
The relationships between polar and rectangular coordinates are:
tan(Θ) = y/x
r² = x² + y²
Given (4, π/6):
tan(π/6) = y/x
1/√3 = y/x
y = x/√3
4² = x² + y²
16 = x² + y²
16 = x² + (x/√3)³
16 = x² + 1/3 x²
16 = 4/3 x²
12 = x²
|x| = √12
|y| = √12/√3 = √4 = 2
(x, y) = (√12, 2) = (2√3, 2)
x = 4cospi/6 = 4(sqrt(3)/2) = 2sqrt(3)
y = 4sinpi/6 = 4(1/2) = 2
(2sqrt(3),2)
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Polar: (r, Θ)
Rectangular: (x, y)
The relationships between polar and rectangular coordinates are:
tan(Θ) = y/x
r² = x² + y²
Given (4, π/6):
tan(π/6) = y/x
1/√3 = y/x
y = x/√3
4² = x² + y²
16 = x² + y²
16 = x² + (x/√3)³
16 = x² + 1/3 x²
16 = 4/3 x²
12 = x²
|x| = √12
|y| = √12/√3 = √4 = 2
(x, y) = (√12, 2) = (2√3, 2)
x = 4cospi/6 = 4(sqrt(3)/2) = 2sqrt(3)
y = 4sinpi/6 = 4(1/2) = 2
(2sqrt(3),2)