What is the concentration of D at equilibrium?
Calculate the Trial Product to determine which direction reaction will take place to reach equilibrium
Q = [C][D] / [A][B]
1.8(2.50) / 1.0(2) = 2.25
Since Q of 2.25 is greater than than the Kc of 0.036, the reaction will proceed
to make more reactants.
Let x = [C] that reacts
At equilibrium: [1.8-x][2.5-x] / [1+x][2+x] = 0.036
4.5 - 4.3x + x^2 / 2+3x + x^2 = 0.036
4.5 - 4.3x + x^2 = 0.072 + 0.108x + 0.036x^2
0.964x^2 – 4.4108x + 4.4428 = 0
x = 1.49
[D] = 2.50 – 1.49 = 1.01 [C] = 0.31
[A] = 2.49 [B] = 3.39
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Calculate the Trial Product to determine which direction reaction will take place to reach equilibrium
Q = [C][D] / [A][B]
1.8(2.50) / 1.0(2) = 2.25
Since Q of 2.25 is greater than than the Kc of 0.036, the reaction will proceed
to make more reactants.
Let x = [C] that reacts
At equilibrium: [1.8-x][2.5-x] / [1+x][2+x] = 0.036
4.5 - 4.3x + x^2 / 2+3x + x^2 = 0.036
4.5 - 4.3x + x^2 = 0.072 + 0.108x + 0.036x^2
0.964x^2 – 4.4108x + 4.4428 = 0
x = 1.49
[D] = 2.50 – 1.49 = 1.01 [C] = 0.31
[A] = 2.49 [B] = 3.39