tg(y) = -√2
tg(2y) =(2tg(y)/(1 - tg(y)²)
tg(2y) = (2(-√2))/(1 - 2) = -2√2/-1 = 2√2
cotg(2y) = 1/2√2 = √2/4
pronto
tg y = -â2
y = -â2/tg
y = tg-1 (-â2)
y = -54,7°
2y = -109,4° ou 250,6°
cotg 2y = 1/tg(2y)
1/tg(250,6°) = 0,35
cotg 250,6° = 0,35
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Verified answer
tg(y) = -√2
tg(2y) =(2tg(y)/(1 - tg(y)²)
tg(2y) = (2(-√2))/(1 - 2) = -2√2/-1 = 2√2
cotg(2y) = 1/2√2 = √2/4
pronto
tg y = -â2
y = -â2/tg
y = tg-1 (-â2)
y = -54,7°
2y = -109,4° ou 250,6°
cotg 2y = 1/tg(2y)
1/tg(250,6°) = 0,35
cotg 250,6° = 0,35