Verified answer

3/(√2 + √3)

multiplique pelo conjugado

3*(√2 - √3)/(√2 - √3)*(√2 + √3) =

(3√2 - 3√3)/(2 - 3) = 3*(√3 - √2)

pronto

3/r2+r5 > 3/r2+r5 x r2-r5/r2-r5 > 3r2-3r5/2-5 > 3(r2-r5)/-3 > -r2+r5

3:(V2+5)=

3(V2-V5):[(V2+V5)(V2-V5)]=

3(V2-V5):[(V2)²-(V5)²]=

3(V2-V5):[2-5]=

3(V2-V5):[-3]=

-(V2-V5)=

V5-V2

vamos la

3/(V2-V5) x (V2+V5)/(V2+V5) = 3(V2+V5)/(2-5)

3(V2+V5)/-3 = -(V2+V5) okkkkkk