https://www.youtube.com/watch?v=Y5zCUpQy6Rw
Hola
Suponemos
∫√(8 + x) dx
Se resuelve con sustituición
u = 8 + x
du = dx
∫√u du
y con potencia fraccionaria
∫ u^(1/2) du
= (1/(3/2)) u^(3/2) + C
= (2/3) (8 + x)^(3/2) + C
= (2/3) √[(8 + x)^3] + C
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Answers & Comments
https://www.youtube.com/watch?v=Y5zCUpQy6Rw
Hola
Suponemos
∫√(8 + x) dx
Se resuelve con sustituición
u = 8 + x
du = dx
∫√u du
y con potencia fraccionaria
∫ u^(1/2) du
= (1/(3/2)) u^(3/2) + C
= (2/3) (8 + x)^(3/2) + C
= (2/3) √[(8 + x)^3] + C