3(x+2)+x²=(x+4).(x+1)
3x + 6 + x² = x² + 4x + 4
3x + 6 + x² - x² - 4x - 4 = 0
-x +2 = 0
x =-2
QSL?
3(x+2)+x²=(x+4).(x+1)
3x+6+x²=x²+5x+4
5x-3x=6-4
2x=2
x=1
3x-5x=4-6
-2x=-2
x=2/2
3x+6 + x² = x²+x +4x+4
x²-x²+3x-5x=4 - 6
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Verified answer
3(x+2)+x²=(x+4).(x+1)
3x + 6 + x² = x² + 4x + 4
3x + 6 + x² - x² - 4x - 4 = 0
-x +2 = 0
x =-2
QSL?
3(x+2)+x²=(x+4).(x+1)
3x+6+x²=x²+5x+4
5x-3x=6-4
2x=2
x=1
3x+6+x²=x²+5x+4
3x-5x=4-6
-2x=-2
2x=2
x=2/2
x=1
3x+6 + x² = x²+x +4x+4
3x+6+x²=x²+5x+4
x²-x²+3x-5x=4 - 6
-2x=-2
x=1
vá estudar poha